iv
) AD = 5.7 cm, BD = 9.5 cm, AE = 3.3 cm and EC =5,5 cm
Ina A ABC, P and Q are points on sides AB and AC respectively, such that PO || BC. If
AP = 24 cm, AQ = 2 cm, QC = 3 cm and BC = 6 cm, find AB and PO,
BC D and Eare points on AB AC respectively
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Step-by-step explanation:
Since; PQ does not bisect AC ; we cannot use midpoint theorem here
First Let's see some valid values for AB as well as PQ;
In ∆ ABC ;
{AC+BC}>AB
: AB will be less than 11cm
I am sorry to tell u but such a ∆ cannot exist because we are given with the value of AP as 24 cm which means AB> 24 cm and thus AB will always be greater than 11cm
But we found previously that AB can be only less than 11cm.
So the final conclusion is that ∆ABC with sides measuring such units will never exist .
Hope this was helpful !
By the way u can correct the values and then reply me to find the solution .
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