Question

IV. Answer the following question:
3x9=27
25. Roopa was younger by 5 years than what she really is, then square of her age (in
years) would have been 11 more than five times her actual age. What is her age
now?​

Answer 1

Answer:

14 years

Step-by-step explanation:

Let Roopa's present age be x years

Hence, it is given that ,

(x-5)

${(x - 5)}^{2} = 11 + 5x$

On solving , we get , x = 1 or 14

but since (x-5) can't be negative ,

Roopa's present age is 14 years