Math, asked by najmaaar786, 5 hours ago

iv) cosec 22° cosec 62° cos 28°cos 68º..
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Answers

Answered by pyalchaudhary123
3

Answer:

cosec(90-68)cosec(90-22)cos28 cos68

=sec68sec22cos28cos68

=1/cos68 (1/cos22)cos28cos68

= 1

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