(iv)' Find the sum of first 100 even natural numbers divisible by 5.
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Answer:
Step-by-step explanation:
this is an AP
10,20,30.............
a=10 d=10
S₁₀₀=100/2[2a+[n-1]d]
=50[2*10+99*10]
=50[20+990]
=50*1010
=50500ans
Anonymous:
hope it helps
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