Question

iv) given a3-15, S10= 125, find d and a10
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Answer 1

Step-by-step explanation:

a

3

=15,s

10

=125

a

3

=a+(3−1)d

15=a+2d

a=15−2d

s

10

=

2

10

[2a+(10−1)d]

125=5[2a+9d]

25=2a+9d

25=2(15−2d)+9d

25=30−4d+9d

5d=−5

d=−1

a=15−2×(−1)

a=17

a

10

=a+(10−1)(−1)

a

10

=17−9

a

10

=26

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