Question

(iv) Mass of the given solid, (m) = (m2 – m1)g = ............
g
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Answer 1

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☆ANSWER☆

We know that 

v=u+at

Here v=0 and a=g

so 0=u+gt

u=−gt --- (i) 

we also know 

v2.u2=2as   ---(ii)

Here v=0,u=−gt from eqn (i) and S=h1 and taking t=t1

putting all above values in eq (ii)

g2t12=2gh1

or 

h1=21gt12  ----(iii)

Similarly for S=h2 and t=t2

h2=21gt22    ----(iv)

Dividing eqn (iii) & (iv) we get,

t2t1=h2h1

The ratio will not change in either case because acceleration remains the same. In the case of free-fall acceleration does not depend upon mass and size of the body.