Question

iv) The binding energy of a satellite revolving
around planet in a circular orbit is 3x10° J.
Its kinetic energy is
(A) 6x10tothepower9J
(B) -3 x10tothepower9J
(C) -6 *10+tothepower9J
(D) 3 x10+to thepower9J​

Answer 1

Answer:

option c is correct....... according to me

Answer 2

iv) The binding energy of a satellite revolving

around planet in a circular orbit is 3x10° J.

Its kinetic energy is

(A) 6x10tothepower9J

(B) -3 x10tothepower9J

(C) -6 *10+tothepower9J

(D) 3 x10+to thepower9J