Question

(iv) The taxi charges in a city consist of a fixed charge together with the charge for the
distance covered. For a distance of 10 km, the charge paid is * 105 and for a
journey of 15 km, the charge paid is * 155. What are the fixed charges and the
charge per km? How much does a person have to pay for travelling a distance of
25 km?
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Answer 1

$\large\underline\pink{Given:-}$

• A distance of 10 km. the change paid is 105 and for a hour of 15 km, the change paid is 155.

$\large\underline\pink{To find:-}$

• Fine the person have to pay for traveling a distance of 25 km ....?

$\large\underline\pink{Solutions:-}$

• Let charges of texi be x
• Let running charge of texi be y.

A distance of 10 km. the change paid is 105

⟹ x + 10y = 105 .......(i).

A journey of 15 km the changer paid is 155.

⟹ x + 15y = 155 .......(ii).

Now, Solving the Eq. (ii) and Eq. (i). we get,

${x} \: + \: {15y} \: \: = \: \: {115} \\ {x} \: + \: {10y} \: \: = \: \: {150} \\ \underline{- \: \: \: \: \: \: \: \: \: - \: \: \: \: = \: \: \: \: \: - \: \: \: \: \: } \\ \: \: \: \: \: \: \: \: \: \: \: {5y} \: \: \: \: \: = \: \: \: {50}$

$\: \: \: \: \: \leadsto \: \: y \: \: = \: \: \cancel{\frac{50}{5}}$

$\: \: \: \: \: \leadsto \: \: y \: \: = \: \: {10}$

Now, putting the value of y in Eq. (i)

$\: \: \: \: \: \leadsto \: \: {x} \: + \: {10y} \: \: = \: \: {105}$

$\: \: \: \: \: \leadsto \: \: {x} \: + \: {10} \: \times \: {10} \: \: = \: \: {105}$

$\: \: \: \: \: \leadsto \: \: {x} \: - \: {100} \: \: = \: \: {105}$

$\: \: \: \: \: \leadsto \: \: {x} \: \: = \: \: {105} \: - \: {100}$

$\: \: \: \: \: \leadsto \: \: {x} \: \: = \: \: {5}$

• Now, A person having to pay for travelling is distance of 25 km

⟹ x + 25y

⟹ 5 + 25 × 10

⟹ 5 + 250

⟹ Rs. 255

Answer 2

Answer:

$refer \: to \: the \: attachment$