Question

iv)The total surface area of the combined figure i.e. hemispherical dome with
radius 14m and cuboidal shaped top with dimensions 8m x 6m x 4m is-
a) 1200 sq.m
b) 1232 sq.m
c) 1393 sq.m
d) 1932 sq.m​

Answer 1

Answer:

1232sq.m

Step-by-step explanation:

Here, radius of hemispherical dome (r) = 14 m

Surface area of dome = 2πr2

= 2 × 22 / 7 × 14 × 14 = 1232 m2

Hence , total surface area to be whitewashed from outside is 1232 m2 ...

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