Question

(iv) What is the emissive power of a perfect blackbody at 1000 K?​

Answer 1

Answer:

Emissive power (E) of a material at a certain temperature is defined as the rate of radiation emitted through a unit area of the material.

Explanation:

Let consider a perfect blackbody which emit Q joule of energy from the area of A m² at a given temperature of T⁰K in t second.

So, the formula for Emissive power(E) = Q/(t * A)

for example, A blckbody emit 1380 joule of energy from the area of 2m² at 300k temperature in 3sec. so, the emissive power og the black body at 300k temperature is, E= Q/t*A

                            = 1380/(3*2)

                            = 230 Jm⁻²s⁻¹