Question

iv. x2 + 5 = -6x by completing the square​

Answer 1

Hello,Buddy!!

||Required Solution||

→ x²+5 = -6x

→ x²+5+6x = 0

→ x²+6x+5 = 0

→ x²+5x+x+5 = 0

→ x(x+5)+1(x+5) = 0

→ (x+5)(x+1) = 0

→ x = -5 & -1

• Value of x ➪ -5 & -1

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Answer 2

SOLUTION :-

Given :-

$→{x}^{2} + 5 = - 6x$

Bringing -6x to LHS,

$→ {x}^{2} + 5 + 6x = 0$

Rearranging the terms,

$→ {x}^{2} + 6x + 5= 0$

Now factorizing the terms,

$→ {x}^{2} + 5x + x + 5= 0$

$→x(x + 5) + 1(x + 5) = 0$

$→(x + 5)(x + 1) = 0$

Therefore, we get,

x = -5 & x = -1

Hence, $\alpha = - 5$ and $\beta = - 1$.