Question

iv. x2 + 5 = -6xfind roots of the following quadratic equation,if they exist
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Answer 1

Answer:

x= -1 ,-5

Step-by-step explanation:

x² + 5 = -6x

x² + 6x + 5

x² +5x + 1x + 5

x( x +5) +1 (x+5)

(x+1) (x+5)

x+ 1=0 ,x +5= 0

x =-1 ,x= -5

Answer 2

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