Question

ix) Acar moves in a circle at the constant speed
of 50 m/s and completes one revolution
in 40 s. Determine the magnitude of
acceleration of the car.
[Ans: 7.85 m s?]
​

Answer 1

Answer:

Explanation:

We know that, distance = speed*time

So, d = 50*40 = 2000m

D = 2*3.14*r (circumference of the circle)

=> 2000=2*3.14*r

On calculating, r = 318.47 m

In this case, required acceleration will be centripetal acceleration.

So, a = (v*v)/r

A = (50*50)/318.47

A = 7.85m/s^2

Hope this helps.