Question

J. An object is at the position of rest. I a
fance of 12 N acts on the object its velocity
20m D and travelo a distance of 60m.
mass of the object is 20 kg then calculate
the amount of Workdone
(​

Answer 1

Given:-

• Force , F = 12 N

• Displacement ,s = 60m

• Mass ,m = 20kg

• Initial Velocity ,u = 0m/s

To Find:-

• Amount of Work Done ,W

Solution:-

As we know that work done is defined when force acting on body and the body covered some distance/displacement then we said the work is done.

• W = Fs

Where,

W is the Work Done

F is the Force

s is the Distance

Substitute the value we get

→ W = 12 × 60

→ W = 720 J

Therefore, the amount of work done is 720 Joules .

Answer 2

Answer:

Given:-

Force (F) = 12 N

Displacement (S) = 60 m

Mass (M) 20 kg

Initial velocity (U) = 0 m/s

To find :-

Amount of Work done (W)

SoluTion:-

As we know that

$\huge \bf \: w \: = fs$

Here,

W = Work done

F = Force applied

S = Displacement

Putting values

$\sf \: w \: = 12 \times 60$

$\huge \bf \: work \: done \: = 720 \: J$

Joule is the SI unit of work(J)