Question

J) Find the area of a rectangular plot, one side of
which is 48 m and its diagonal is 50 m.​

Answer 1

Answer:

Step-by-step explanation:

A . T Pythagoras theorems

h2= b2 + p2

50² = 48² + p²

2500 = 2304 + p²

p² = 2500 - 2304

p =√196=14 m

Area = length x breadth

14 x 48

= 672 m²

Answer 2

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Let ABCD be the rectangular plot. T

hen, AB = 48 m and AC = 50 m BC =?

According to Pythagoras theorem,

From right angle triangle ABC,

we have:

$\tt{= AC² = AB² + BC² } \\ \tt{= 50² = 48² + BC² } \\ \tt{= BC² = 50² – 48² }\\ \tt{= BC² = 2500 – 2304} \\ \tt{= BC² = 196} \\ \tt{= BC = \sqrt{196} } \\ \tt{= BC = 14 m}$

Hence, the area of the rectangle plot = (l × b)

Where, l = 48 m, b = 14 m

Then, = (48 × 14) = 672 m²

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$\LARGE\mathfrak{\underline{\underline{\purple{Learn~ more !! }}}}$

In the triplet of natural numbers, the square of the biggest number is equal to the sum of the square of the two numbers, then the three numbers from a Pythagorean triplet. If the lengths pf three sides of a triangle from such a triplet, then the triangle is a right - angled triangle.

Example: Do the following numbers from a Pythagorean triplet : (7, 24, 25)?

Solution: 7² = 49, 24² = 576, 25² = 625

⠀⠀⠀⠀⠀⠀⠀⠀$\therefore$ 49 + 576 = 625

⠀⠀⠀⠀⠀⠀⠀⠀⠀$\therefore$ 7² + 24² = 25²

⠀⠀⠀⠀➠ 7, 24, 25 is a Pythagorean triplet.