Question

J. Which of the following sets are equal sets ?

(ii) {1,2,3}, {x:x2 - 2x + 1 = 0 }, { 3, 2, 1 }, { x:x3 - 6x2 + 11x - 6 = 0} plz Give the complete solution not just answer...​

Answer 1

Answer:

(i) A = {1, 2, 3} (ii) B = {x ∈ R : x2 - 2x + 1 = 0} (iii) C = {1, 2, 3, 4} ( iv) D = {x∈ R: x3 - 6x2 + 11x - 6 = 0} .

Answer 2

Answer:

The groups have no common factor and can not be added up to form a multiplication.

Step-by-step explanation:

x=3 x=2 x=1

"x2"   was replaced by   "x^2".  1 more similar replacement(s).

(((x3) -  (2•3x2)) +  11x) -  6  = 0

 x3-6x2+11x-6  is not a perfect cube

Factoring:  x3-6x2+11x-6

Thoughtfully split the expression at hand into groups, each group having two terms :Group 1:  11x-6  Group 2:  -6x2+x3

Pull out from each group separately :Group 1:   (11x-6) • (1) Group 2:   (x-6) • (x2)