Physics, asked by Anonymous, 1 year ago

Jai bajarang bali

Hello brainliacs

Ques. In an experiment 4 quantities a, b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively. Quantity P is calculated as follows

p =  \frac{ {a}^{3} {b}^{2}  }{cd}  \: \% \: error \: in \: p \: is \:

?????????????

Answer should be doubt free.

Thanks

Answers

Answered by kevinujunioroy492d
3
error in p

=3×error in a +2×error in b+error in c +error in d
=3×1+2×2+1×3+1×4
=11%


we did this because percentage error of a quantity in multiplication or division are simply added with multiplication of their powers


kevin:)
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Anonymous: Thanks bhai
Anonymous: Ans is 14 %
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kevinujunioroy492d: sorry mistake hogi
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Anonymous: Yes bro
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Answered by Anonymous
0

Answer:

Explanation:

Hope you understood.

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