Question

jaldi ans karo...... ​

Answer 1

Answer:

don't know...

..........

Answer 2

Given :

In triangle PQR, XY || QR ,M and N are midpoints of PY and PR .

∴ PM=MY= MN

and PY=YR

∴PY=2PM

and YR=2PM=2MN

solution :

since XY || QR

then by basic proportionality theorem:

$\frac{px}{xq} = \frac{py}{yr}$

$\frac{px}{xq} = \frac{2pm}{2mn}$

1. proof :Δ PXM ≈ Δ PQN

In ᐃPXM and Δ PQN,

PX / XQ = PM/MN

angle P = angleP ( common )

∴ SAS similarity criteria,

Δ PXM ≈ Δ PQN

2. proof : XM || QN

since Δ PXM ≈ Δ PQN

we have ;

PX / XQ = PM / MN

by converse of BPT

XM || QN

follow me

mark answer as brainlist