Question

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Answer 1

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Answer 2

Answer:

So first up is ... squaring the given equation...

$(sin A+cos A)^{2} =1^{2}\\ sin^{2}A+cos ^{2}A+2sinAcosA=1\\1+2sinAcosA=1 \\2sinAcosA=0\\sinAcosA=0\\\\\\sin^{3}A+cos^{3}A\\=(sinA+cosA)(sin^{2}A+cos^{2}A+sinAcosA)\\=(1)(1+0)\\=1*1\\=1$

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