Question

Jame's age is six times his son's age.Twenty years ago he was ten times his son age. Find their present age.​

Answer 1

$\large{\underline{\red{\rm{Let:}}}}$

• The present age of James be 6X
• The present age of his son be X

$\large{\underline{\red{\rm{To\:Find:}}}}$

• Their present age

$\large{\underline{\red{\rm{A.T.Q:}}}}$

20 years ago he was 10 times of his sons age

⟹6X-20=10(X-20)

⟹6X-20=10X-200

⟹10X-6X=-20+200

⟹4X=180

⟹$\cancel{4}X=\cancel{180}$

⟹X=45

Hence,

The present of James=6×45=270 year's

The present of his son=45 year's

$\large{\underline{\red{\rm{AnswEr:}}}}$

$\large{\boxed{\green{\rm{James's\:age=270\: year's:}}}}$

$\large{\boxed{\purple{\rm{His\:son's\:age=45\: year's:}}}}$

Answer 2

QuEsTiOn :-

Jame's age is six times his son's age.Twenty years ago he was ten times his son age. Find their present age.

SoLuTiOn :-

Let the present age of son = x

and present age of Jame's = 6x

Given :-

• Twenty years ago :-

The present age of son = x - 20

and present age of Jame's = 6x - 20

According to question

6x - 20 = 10(x - 20)

=> 6x - 20 = 10x - 200

=> 6x - 10x = - 200 + 20

=> - 4x = - 180

=> 4x = 180

=> x = 180/4

=> x = 45

So,

Present age of son = 45 and ,

Present age of Jame's = 6x = 6×45 = 270

Answer

${\purple{\boxed{\large{\bold{</u><u>Present </u><u>\</u><u>:</u><u> </u><u>age</u><u> </u><u>\</u><u>:</u><u> </u><u>of</u><u> </u><u>\</u><u>:</u><u>son</u><u> </u><u>=</u><u> </u><u>4</u><u>5</u><u> </u><u>years</u><u> </u><u>}}}}}$

${\</u><u>r</u><u>e</u><u>d</u><u>{\boxed{\large{\bold{</u><u>Present </u><u>\</u><u>:</u><u> </u><u>age </u><u>\</u><u>:</u><u> </u><u>of</u><u> </u><u>\</u><u>:</u><u> </u><u>Jame's</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u>0</u><u> </u><u>years</u><u> </u><u>}}}}}$