Janae and Jerome each have m marbles. Gwen has 4(m + 2) marbles. John has 8m + 4 marbles. If John has more marbles than Janae, Jerome, and Gwen combined, how many marbles might Janae and Jerome each have?
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Answered by
42
Ans.
Let us take :
Janae = A
Jerome = B
Gwen = C
John = D
Given that
D > A + B + C
or, 8m + 4 > (m) + (m) + (4m + 8)
or, 8m + 4 > 6m + 8
or, 2m > 4
or, m > 2
Here, m belongs to the set of Natural numbers.
So, we can take
m = 3, 4, 5, ...
For example, we take m = 3.
Then, Janae has 3 marbles,
Jerome has 3 marbles,
Gwen has 20 marbles and
John has 28 marbles.
You can also put m = 4, 5, ... and you will get more answers.
*** I HOPE THAT THIS HELPS YOU ***
Let us take :
Janae = A
Jerome = B
Gwen = C
John = D
Given that
D > A + B + C
or, 8m + 4 > (m) + (m) + (4m + 8)
or, 8m + 4 > 6m + 8
or, 2m > 4
or, m > 2
Here, m belongs to the set of Natural numbers.
So, we can take
m = 3, 4, 5, ...
For example, we take m = 3.
Then, Janae has 3 marbles,
Jerome has 3 marbles,
Gwen has 20 marbles and
John has 28 marbles.
You can also put m = 4, 5, ... and you will get more answers.
*** I HOPE THAT THIS HELPS YOU ***
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i am a math teacher
I am a Math student.
u may be a student but i have done phd in algaebra
and in maths subject
Then, you did a bad thing, Mr. Teacher.
Ok. I hate arguing with any teacher.
You win.
I am wrong.
Bye.
ok
Answered by
2
Answer:
m < 4
Step-by-step explanation:
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