Question

Jane is 6 years older than her younger sister. After 10 years,the sum of their ages will be 50 years. find their present ages

Answer 1

let the age of Jane younger sister is x.
so the Jane age will be 6+x
after 10 years their age will be
x+10,x+6+10
x+10+x+6+10=50
2x+26=50
2x=50-26
2x=24
x=24/2
x=12
Her younger sister age is=12
Jane age is=x+6
12+6=18

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Answer 2

Answer:

Her younger sister's age is=12

Jane's age = 18

Step-by-step explanation:

Let the age of Jane younger sister is y,

so the Jane age will be 6+y

after 10 years their age will be

y+10,y+6+10

(y+10)+(y+6+10)=50

2y+26=50

2y=50-26

2y=24

y=24/2

y=12

Her younger sister age is=12

Jane age is=y+6

12+6=18