Question

Jane is six years older than her younger sister.Aftet 10 years,the sum of their ages will be 50 years.find their present ages​

Answer 1

Answer:

Jane = 18

Younger Sister = 12

Step-by-step explanation:

Let the age of Jane’s younger sister is x.

Age of Jane will be x + 6

As per the question, after 10 years the sum of their ages will be 50.

After 10 years,

age of Jane = x + 16

age of her younger sister = x + 10

Therefore,

x + 16 + x +10 = 50

2x + 26 = 50

2x = 24

x = 12

Thus, the present age of Jane’s younger sister is 12 years.

And of Jane’s is 12+6 = 18 years.

Thanks