Chemistry, asked by sakethreddy5086, 1 month ago

Jane performed the following trials in an experiment. Trial 1: Heat 80.0 grams of water at 15.0 °C to a final temperature of 65.0 °C. Trial 2: Heat 80.0 grams of water at 10.0 °C to a final temperature of 65.0 °C. Which statement is true about the experiments?

Answers

Answered by suhani9989
1

Explanation:

The heat absorbed in Trial 2 is about 18420 J greater than the heat absorbed in Trial 1 (16740 J). Explanation: The amount of heat absorbed by water (Q) can be calculated from the relation: Q = m.c.ΔT. where, Q is the amount of heat absorbed by water, m is the mass of water, c is the specific heat capacity of water (c = 4.186 J/g °C), ΔT is the temperature difference (final T - initial T).

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Answered by imaanz456
13

Answer:

the heat absorbed in Trial 2 is about 1,674 J greater than the heat absorbed in Trial 1

Explanation:

use the formula Q = m*c* change in temp

c is the specific heat capacity, m is the mass of water

trial 1: 80*4.186*50 = 16744

trial 2: 80*4.186*55 = 18418.4

trial 2 absorbed 1674 more J

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