Jannat is 6 years older than her younger sister after 10 years the sum of their ages will be 50 years find their present ages
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Hey there!
=> Let the age of Jannat's younger sister be x.
=> Let the age of jannat be (x+6). [ 6 years older means 6 added to her younger sister's age]
=> After 10 years, [Simply add 10 to both the ages as it's ten years "after"]
=> Age of jannat's younger sister will be (x+10) and Age of jannat will be (x+6+10).
=> Therefore as given in the question, after 10 years their sum of the ages will be 50:
(x+10) +(x+6+10) = 50
2x +26 =50
2x = 50-26
2x =24
x = 24 /2 =12
x=12
=> The present age of jannat's younger sister is 12( x) and jannat is 18 (x+6).
Ans: 12 years and 18 years.
hope it Helps!!!!☺️
=> Let the age of Jannat's younger sister be x.
=> Let the age of jannat be (x+6). [ 6 years older means 6 added to her younger sister's age]
=> After 10 years, [Simply add 10 to both the ages as it's ten years "after"]
=> Age of jannat's younger sister will be (x+10) and Age of jannat will be (x+6+10).
=> Therefore as given in the question, after 10 years their sum of the ages will be 50:
(x+10) +(x+6+10) = 50
2x +26 =50
2x = 50-26
2x =24
x = 24 /2 =12
x=12
=> The present age of jannat's younger sister is 12( x) and jannat is 18 (x+6).
Ans: 12 years and 18 years.
hope it Helps!!!!☺️
prateekking:
thanks
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