Math, asked by ishanpatilpune, 9 months ago

Jar I contains 5 white and 7 black balls. Jar II contains 3 white and 12 black balls. A fair coin is flipped; if it is Head, a ball is drawn from Jar I, and if it is Tail, a ball is drawn from Jar II. Suppose that this experiment is done and a white ball was drawn. What is the probability that this ball was in fact taken from Jar II?​

Answers

Answered by pandiyanj
0

Answer:

Step-by-step explanation:

This can be found using Bayes' theorem.

Say that is the even that the outcome of the toss was heads, and is the even that the white ball was selected.

(|)=29, because that means the first urn was used.

()=0.5, because the coin is fair.

()=0.529+0.5511, by the Law Of Total Probability.

Using Bayes' law, you can get (|) from this.

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