Question

Jaspal bought 2 TV for Rs. 30000. By selling
one at a loss of 15% and other at a profit of
19%, he found that selling price of both TV
sets is same. Find the cost price of each TV.​

Answer 1

Answer:

cost price of 1st TV = 17500

cost price of 2nd TV = 12500

Step-by-step explanation:

let cost price of 1st TV be x

cost price of 2nd TV be y

total cost of TV is 30000

x + y = 30000

1st TV sold at loss of 15%

$= x - 15\%x \\ = x - \frac{15x}{100} \\ = \frac{100x - 15x}{100} \\ = \frac{85x}{100}$

2nd TV sold at profit of 19%

$= y + 19\%y \\ = y + \frac{19y}{100} \\ = \frac{100y + 19y}{100} \\ = \frac{119y}{100}$

it's given that selling price of both TV is same

$\frac{85x}{100} = \frac{119y}{100} \\ 85x = 119y \\ 85x - 119y = 0 \\ 17(5x - 7y) = 0 \\ 5x - 7y = 0$

5x -7y = 0 equ (1)

we know that x + y = 30000

multiply with 7

7x + 7y = 210000 equ (2)

adding (2) and (1)

12x = 210000

x = 210000/12

x = 17500

x + y = 30000

17500 + y = 30000

y = 30000 - 17500

y = 12500

hope you get your answer