Question

Jatin has a mass of 50 kg and takes 5s to reach the first floor that is located 8 m above the ground. Find the (a) gravitational force acting on Jatin (b) work done by a Jatin against gravity (c) Power developed by Jatin given g = 10 ms^-2​

Answer 1

Answer:

A boy of mass kg runs upstairs and reaches the 8 m high floor in 5 s Calculate: the force of gravity acting on the boy. (i) the work done by him against gravity. (ii) the power spent by boy.te

Explanation:

Mass of boy = 40 kg Vertical height moved, h = 8m Time taken, t = 5s. (i) Force of gravity on the boy F = mg = 40 × 10 = 400N  (ii) While climbing, the boy has to do work against the force of gravity. Work done by the boy in climbing= Force × distance moved in the direction of force Or, W = F x S= 400 x 8= 3200 J Power spent = work done/time taken = 3200/5 = 640 WRead more on Sarthaks.com - https://www.sarthaks.com/143344/a-boy-of-mass-kg-runs-upstairs-and-reaches-the-8-m-high-floor-in-5-s-calculate