jay bharti kavita ka mool bhav
Answers
Answer:
ircle the main clauses and underline the subordinate clauses
in these sentences.
1. She was ten years old when she moved to Chennai.
2. It was her essay which got chosen for the school magazine.
3. He came home because it was too hot.
4. Rati studied hard so that she could become an engineer.
5. While they were away, their house was robbed.
6. George behaved as though he had not heard me at all.
Answers:ircle the main clauses and underline the subordinate clauses
in these sentences.
1. She was ten years old when she moved to Chennai.
2. It was her essay which got chosen for the school magazine.
3. He came home because it was too hot.
4. Rati studied hard so that she could become an engineer.
5. While they were away, their house was robbed.
6. George behaved as though he had not heard me at all.
Answers:
Explanation:
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Answer:
Answer:
{\underline{\underline{\maltese\textbf{\textsf{\red{Question}}}}}}✠Question
: \implies{\sf\bigg({\dfrac{x}{2} - 6}\bigg) = \bigg({8 - \dfrac{2x}{3}} \bigg)}:⟹(2x−6)=(8−32x)
\begin{gathered}\end{gathered}
{\underline{\underline{\maltese\textbf{\textsf{\red{Solution}}}}}}✠Solution
: \implies{\sf\bigg({\dfrac{x}{2} - 6}\bigg) = \bf\bigg({8 - \dfrac{2x}{3}} \bigg)}:⟹(2x−6)=(8−32x)
{: \implies{\sf\bigg({\dfrac{x - (6 \times 2)}{2}}\bigg) = \bf\bigg({\dfrac{(8 \times 3) - 2x}{3}} \bigg)}}:⟹(2x−(6×2))=(3(8×3)−2x)
{: \implies{\sf\bigg({\dfrac{x - 12}{2}}\bigg) = \bf\bigg({\dfrac{24 - 2x}{3}} \bigg)}}:⟹(2x−12)=(324−2x)
By cross multiplication
: \implies\sf{3(x - 12) = \bf{2(24 - 2x)}}:⟹3(x−12)=2(24−2x)
: \implies\sf{3x - 36 = \bf{48 - 4x}}:⟹3x−36=48−4x
: \implies\sf{4x - 3x = \bf{48 -36}}:⟹4x−3x=48−36
: \implies\sf{x = \bf{12}}:⟹x=12
{\dag{\underline{\boxed{\sf{x =12}}}}}†x=12
Hence, The value of x is 12.
\begin{gathered}\end{gathered}
{{\underline{\underline{\maltese\textbf{\textsf{\red{Verification}}}}}}}✠Verification
: \implies{\sf\bigg({\dfrac{x}{2} - 6}\bigg) = \bf\bigg({8 - \dfrac{2x}{3}} \bigg)}:⟹(2x−6)=(8−32x)
Substituting the value of x
: \implies{\sf\bigg({\dfrac{12}{2} - 6}\bigg) = \bf\bigg({8 - \dfrac{2 \times 12}{3}} \bigg)}:⟹(212−6)=(8−32×12)
: \implies{\sf\bigg({\dfrac{12}{2} - 6}\bigg) = \bf\bigg({8 - \dfrac{24}{3}} \bigg)}:⟹(212−6)=(8−324)
{: \implies{\sf\bigg({\dfrac{12 - (6 \times 2)}{2}}\bigg) = \bf\bigg({\dfrac{(8 \times 3) - 24}{3}} \bigg)}}:⟹(212−(6×2))=(3(8×3)−24)
{: \implies{\sf\bigg({\dfrac{12 -12}{2}}\bigg) = \bf\bigg({\dfrac{24 - 24}{3}} \bigg)}}:⟹(212−12)=(324−24)
{: \implies{\sf\bigg({\dfrac{0}{2}}\bigg) = \bf\bigg({\dfrac{0}{3}} \bigg)}}:⟹(20)=(30)
: \implies\sf{0} = \bf{0}:⟹0=0
\dag{\underline{\boxed{\sf{LHS=RHS}}}}†LHS=RHS
Hence Verified!!