Math, asked by prachi1590, 1 day ago

jayant bought 4/5 kg of dry fruit . he ate 2/5kg how much of dry fruit was left
please answer me

*step by step*​

Answers

Answered by ruvvasarathchandra
3

Answer:

jayanth total dry fruits par =4/5kg

he Aten 2/5kg from 4/5kg

let remaining left part of dry fruit=x

Aten part + remaining left part =total part

2/5+x=4/5

2/5 transport to right the it become -2/5

x=4/5-2/5

denominators are same so

x=2/5kg

Answered by adcatvns
0

hello \: user \:  \\ your \: question \: solution \\ total \: mass \: of \: dry \: fruit \:  =  \frac{4}{5} kg \\  \\ mass \: of \: dry \: fruit \: eaten \:  =  \frac{2}{5} kg \\  \\ remaining \: dry \: fruits \: mass \:  = ( \frac{4}{5}  -  \frac{2}{5} )kg \\  \\ l \: c \: m \:  = 5 \\  \frac{4 - 2}{5} kg =  \frac{2}{5} kg

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