Chemistry, asked by Prep4JEEADV, 8 months ago

JEE ARCHIVE:- Calculate the amount of Calcium oxide required when it reacts with 852 gram of $P_4O_{10}$

Write the balanced equation needed to solve the equation.

Answers

Answered by Draxillus

Given

852 gram $P_4O_{10}$

To Find

Amount of Calcium oxide (CaO) required.

Concept

Consider the reaction :-

$\green{xA\:+\:yB\:\longrightarrow\:mC\:+\:nD}$

x mole of A is required to react with y moles of B to form m moles of C and n moles of D.

If one of the reactant is less than the required quantity, then it is known as limiting reagent and reaction is determined by the concentration of this limiting reagent.

Solutions

The balanced chemical reaction of CaO with $P_4O_{10}$ is shown here :-

$\green{6CaO\:+\:P_4O_{10}\:\longrightarrow\:2Ca_3{(PO_4)}_2}$

$\textsf{Now, number of moles of}\: P_4O_{10} \:= \: \dfrac{Given\:weight}{Molar\:weight}\\ \\ \\ = \dfrac{852}{284} \\ \\ \\ \textsf{Number of moles of CaO required}\:= 6\times \textsf{number of moles of}\: P_4O_{10}\\ \\ \\ = 6\times \dfrac{852}{284}\\ \\ \\\textsf{Weight of Cao required}\:= 6\times \dfrac{852}{284}\: \times\:56 \:\:(\because\:molar\:mass\:of\:CaO\:=56\:gram)\\ \\ \\ = 1008 gram$

$\boxed{\boxed{\green{Hence\:weight\:of\:CaO\:required\:is\:1008\:gram}}}$

Answered by rosey25

Answer:

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