Question

JEE level question. Wrong answers will be deleted. 100 points. I know the answer but I need 100% correct method. Best Of Luck.​

Answer 1

Discriminant of a quadratic equation D, is given by ;

D = b2 – 4ac 

It is determined from the coefficients of the equation ax2 + bx + c = 0. 

The value of D reveals what type of roots the equation has.

If D is greater than 0, we get real roots

For ax2 + bx + 2 = 0 

The discriminant = b2 – 4(a)(2)

                               = b2 – 8a

Equating this to 0

b2 – 8a = 0

8a = b2

a = b2/8

a and b are positive integers and b is less than 6

the values that b can take include: 1, 2, 3, 4, 5

when, b =1, a = 1/8

b =2, a = 4/8 = ½

b = 3, a = 9/8

b =4, a = 16/8 = 2

b = 5, a = 25/8

The only value of b that gives an integer value of a is 4

Hence, There is only one equation that can be formed that satisfy this condition.

Hope it helps....

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Answer 2

Answer:

The answer is 6545