JEE Mains Maths question is in the image
Attachments:
Answers
Answered by
0
Answer:
(4) increasing in (-1,0) and decreasing in ( 0,infinity )
Answered by
3
It has given that f(x) = ln(1 + x)/x , x ∈ (-1, ∞) and f(0) = 1
we have to check f(x) is ...
- decreasing in (-1, 0) and increasing in (0, ∞)
- always increasing
- always decreasing
- increasing in (-1, 0) and decreasing in (0, ∞)
solution : function, f(x) = ln(1 + x)/x
differentiating f(x) w.r.t x we get,
f'(x) = {xd(ln(1 + x))/dx - ln(1 + x) dx/dx}/x²
= {x/(1 + x) - ln(1 + x)}/x²
= {x - (1 + x)ln(1 + x)}/(1 + x)x²
in (-1, ∞), (1 + x)x² > 0
so, we have to check {x - (1 + x)ln(1 + x) }
let g(x) = x - (1 + x)ln(1 + x)
but g(x) < 0 for all x ∈ (-1, ∞)
so, f'(x) < 0 for all x ∈ (-1, ∞)
Therefore f(x) is always decreasing in (-1,∞) i.e., the correct option is (3).
Similar questions