JEE Mains question is in the image
Attachments:
Answers
Answered by
0
Answer:
c is your proper answer
Answered by
1
Glucose --- HNO₃, (AC)₂O -----> X
--- (AC)₂O ---------------> Y
--- H₂/Ni, (AC)₂O -----> Z
we have to calculate required moles of (AC)₂O in X, Y and Z product formation.
solution : when glucose is treated with HNO₃ , saccharic acid forms and then it is treated with (AC)₂O, gives COOH-(CH-OAc)₄-COOH.
here it is clear that 4 moles (Ac)₂O are required.
similarly, treating glucose directly with (Ac)₂O, gives CHO - (CH-OAc)₄ - CH₂OAc , require 5 moles of (Ac)₂O.
glucose + H₂/Ni -> CH₂OH - (CHOH)₄ - CH₂OH + (Ac)₂O -> CH₂OAc - (CH-OAc)₄ - CH₂OAc , require 6 moles of (Ac)₂O.
Therefore required moles of (Ac)₂O in X , Y , Z product formation are 4, 5, 6 respectively.
Similar questions
English,
4 months ago
Biology,
4 months ago
History,
4 months ago
Physics,
8 months ago
Social Sciences,
1 year ago