Math, asked by 545abul, 28 days ago

JEE MAINS SOLVE THE ATTACHED QUESTIONS ❓

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Answered by VεnusVεronίcα
52

34) A ball falls on the ground from a height of 2.0m and rebounds upto a height of 1.5m. Then the coefficient of restitution is?

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  \red{ \pmb{\sf \qquad :  \implies \: h =  {e}^{2} \:   h_{0} }}

 \red{ \pmb{ \sf \qquad:  \implies \: e =  \sqrt{ \dfrac{h}{ h_{0} } } }}

 \red{ \pmb{\sf{ \qquad :  \implies \: e = \dfrac{ \sqrt{3} }{2}  \:  \: \:  \:  \:   \:  \{0ption \: b \}}}}

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35) A pendulum is released from point A as shown in the figure. Find it's speed as it reaches point B.

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 \red{ \pmb {\sf{ \qquad: \implies \: v = \sqrt{ 2gl}  }}}

 \red{ \pmb{ \sf{ \qquad :  \implies \: v =  \sqrt{2 \: (10) \: (0.5)} }}}

 \qquad \red{ \pmb {\sf{  : \implies \: v =  \sqrt{10}  \: m {s}^{ - 1} }}}

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36) A pendulum is released from θ = 90°. Find the speed at θ = 30°. l = 1m.

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 \red{ \pmb{ \sf{ \qquad  :  \implies  \:h =}}}  \: \red l \pmb{ \sf   \red{\: cos 30 \degree}}

 \red{ \pmb{ \sf{ \qquad :  \implies \: mgh =  \dfrac{1}{2}m {v}^{2}  }}}

 \red{ \pmb {\sf{ \qquad :  \implies \: {v}^{2}  = 2gh }}}

 \red{ \pmb { \sf{ \qquad :  \implies \:  {v}^{2} = 2g \times}}}  \:  \red{l } \red{ \pmb { \sf{\: cos30 \degree }}}

 \red{ \pmb { \sf { \qquad :  \implies \:  {v}^{2}  = 2 \times   10 \times 1   \times  \dfrac{ \sqrt{3} }{2} }}}

 \red{ \pmb { \sf{ \qquad :  \implies \: {v}^{2}   = 10 \sqrt{3} }}}

 \red{ \pmb { \sf { \qquad :  \implies \:  {v}^{2} \approx4m {s}^{ - 1}  }}}

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