Physics, asked by kaverimallarapu721, 1 year ago

Jeep starts from rest and attains a speed of 36 kilometre per hour in 10 seconds calculate the acceleration

Answers

Answered by Linna
14

u=0

v=36km/hr

=10m/s

t=10s

a=(v-u)/t

=(10-0)/10

=10/10

=1m/s^2

Therefore acceleration=1m/s^2

Hope it helps...........

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