jf x+1/X =17/4 THEN FIND THE VALUE OF X
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Answered by
1
Answer:
4 or 1 / 4
Step-by-step explanation:
⇒ x + 1 / x = 17 / 4
⇒ ( x^2 + 1 ) / x = 17 / 4
⇒ 4( x^2 + 1 ) = 17x
⇒ 4x^2 + 4 = 17x
⇒ 4x^2 - 17x + 4 = 0
⇒ 4x^2 - ( 16 + 1 )x + 4 = 0
⇒ 4x^2 -16x - x + 4 = 0
⇒ 4x( x - 4 ) - ( x - 4 ) = 0
⇒ ( x - 4 )( 4x - 1 ) = 0
⇒ x - 4 = 0 or 4x - 1 = 0
⇒ x = 4 or x = 1 / 4
Answered by
0
x+1/x=17/4
=(x^2+1)×4 = 17x
=4x^2+4 =17x
=4x^2-17x+4=0
=x=-b+/-root over b^2-4ac/2a
X= -(-17)+/- root over (17)^2-4(4)(4)/2(4)
X=17+/- root over 289-64/8
X=17+/- root over 225/8
X=17+/- 15/8
X=17+15/8, X=17-15/8
X=32/8,2/8
X=4,1/4
so this is ur answer
please MARK as BRAINLIST answer
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