Math, asked by sharukhmoosa, 9 months ago

jf x+1/X =17/4 THEN FIND THE VALUE OF X​

Answers

Answered by abhi569
1

Answer:

4 or 1 / 4

Step-by-step explanation:

 ⇒ x + 1 / x = 17 / 4

⇒ ( x^2 + 1 ) / x = 17 / 4

⇒ 4( x^2 + 1 ) = 17x

⇒ 4x^2 + 4 = 17x

⇒ 4x^2 - 17x + 4 = 0

⇒ 4x^2 - ( 16 + 1 )x + 4 = 0

⇒ 4x^2 -16x - x + 4 = 0

⇒ 4x( x - 4 ) - ( x - 4 ) = 0

⇒ ( x - 4 )( 4x - 1 ) = 0

⇒ x - 4 = 0   or  4x - 1 = 0

⇒ x = 4   or   x = 1 / 4

Answered by anu012
0

x+1/x=17/4

=(x^2+1)×4 = 17x

=4x^2+4 =17x

=4x^2-17x+4=0

=x=-b+/-root over b^2-4ac/2a

X= -(-17)+/- root over (17)^2-4(4)(4)/2(4)

X=17+/- root over 289-64/8

X=17+/- root over 225/8

X=17+/- 15/8

X=17+15/8, X=17-15/8

X=32/8,2/8

X=4,1/4

so this is ur answer

please MARK as BRAINLIST answer

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