Question

jharna got Rs 1881 interest of certain sum for 2 years at 9% compound yearly. what was the sum deposited?​

Answer 1

Answer:-

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Given:

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▪︎Compund Interest(C.I.) = Rs.1881

▪︎Time(T) = 2 years

▪︎Rate%(r) = 9% compounded yearly

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To Find:

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▪︎Sum of money deposited (Principal(P))

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Solution:

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Let the sum of money deposited be x

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According to given conditions;

Compound Interest = Rs.1881

$\sf{}\implies Amount - Principal = Rs.1881$

$\sf{}\implies P×{(1+\frac{r}{100})}^{T} - P= Rs.1881$

$\sf{}\implies x×{(1+\frac{9}{100})}^{2} - x= Rs.1881$

$\sf{}\implies \frac{11881x}{10000} -x= Rs.1881$

$\sf{}\implies \frac{11881 x}{10000}-x= Rs.1881$

$\sf{}\implies \frac{11881x-10000x}{10000}= Rs.1881$

$\sf{}\implies 1881x = 1881 × 10000$

$\sf{}\implies x = \frac{\cancel{1881}×10000}{\cancel{1881}}$

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$\boxed{\pink{\bf{\therefore x = Principal = Rs.10000}}}$

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Formula to be remembered:-

▪︎$\sf{}Amount = Principal×{(1+\frac{Rate}{100})}^{Time}$

▪︎Compound Interest = Amount - Principal

Answer 2

Answer:

Step-by-step explanation:

1000