Jim and Pam were on a holiday in the Amazon rainforest. Pam saw a bush of beautiful flowers that she wanted to make a garland out of, but this was across the river and they would have to jump 10 rocks to get across. They both carried old, worn-out baskets and on the return trip, Pam lost two flowers from a big hole in his basket at every jump. Jim was right behind her and he too lost two flowers at every jump, but also managed to catch one of Pam's lost flowers at every alternate jump. If they got back with a total of 37 flowers between the two of them, how many flowers did they collectively pick before they crossed the river assuming that they both collected an equal amount of flowers?
Answers
Given :-
- Total rocks in river for jump = 10 .
- Pam lost flowers in every jump = 2 .
- Jim lost flowers in every jump = 2 .
- Jim catch flowers in alternate jump = 1 .
- Total flowers they got back with = 37
To Find :-
- Total flowers they collectively pick = ?
Solution :-
→ Total rocks = 10
as we can say that, from forest to first rock in river they have 1 jump and from 10 to again in forest they have 1 jump .
so,
→ Total jumps they need to cross 10 rocks = 10 + 1 = 11 .
now,
→ Flowers lost by Pam in each jump = 2
then,
→ Flowers lost by Pam in 11 jumps = 11 * 2 = 22 flowers.
similarly,
→ Flowers lost by Jim in each jump = 2
then,
→ Flowers lost by Jim in 11 jumps = 11 * 2 = 22 flowers.
also,
→ Flower catch by Jim in alternate jump = 1
now,
→ Total alternate jumps by Jim = 5 .
then,
→ Flower catch by Jim = 5 * 1 = 5 flowers .
therefore,
→ Total flowers = flowers in last + Flowers lost by Pam + Flowers lost by Jim - Flower catch by Jim
→ Total flowers = 37 + 22 + 22 - 5 = 76 flowers.
Hence,
→ flowers picked by each of them = 76 / 2 = 38 flowers. (Ans.)
Learn more :-
Shakuntla Devi, Karl Gauss, Archimedes could do a lot of quick maths since their young ages.
Can you do better and find ...
https://brainly.in/question/37519368