Question

Jiya walks 6 km due east and then 8 km due north. How far is she from her starting place?

Answer 1

$\textbf{\huge{ANSWER:}}$

$\tt{Given\:that}$:

Jiya walks $\textbf{6km east}$

And then $\textbf{8km north}$

Now, jus make the figure of this question. The figure is given in the attachment.

We need to find the length of $\textbf{AC}$

By the $\textbf{Pythagoras Theorem}$:

$H^{2} = P^{2} + B^{2}$

=》 $AC^{2} = AB^{2} + BC^{2}$

=》 $AC^{2} = 6^{2} + 8^{2}$

=》 $AC^{2} = 36 + 64$

=》 $AC = \sqrt{100}$

=》 $\textbf{AC = 10 km}$

Therefore, Jiya is 10 km far from her home position.

Answer 2

Answer:

Hope it's helpful..

Step-by-step explanation:

Let B be the end point while A is the starting point of Jiya.

Triangle ABC is a right-angled.

(AB) 2=6 2 +8 2

⇒ AB= 36+64

⇒ AB= 100

⇒ AB=10km