Math, asked by tanvi524, 10 months ago

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Answered by anu24239
2

SOLUTION

 \frac{x + 1}{2}  +  \frac{y - 1}{ 3}  = 9 \\ take \: lcm \\  \frac{3(x + 1) + 2(y - 1)}{6}  = 9 \\  \frac{3x + 3 + 2y - 2}{6}  = 9 \\ 3x + 2y + 1 = 54 \\ 3x + 2y = 53.......eq(1) \\  \\  \\  \frac{x - 1}{3}  +  \frac{y + 1}{2}  = 8 \\ 2(x - 1) + 3(y + 1) = 48 \\ 2x - 2 + 3y + 3 = 48 \\ 2x + 3y + 1 = 48 \\ 2x + 3y = 47........eq(2) \\  \\ 3x + 2y = 53 (multiply \: by \: 2)\\ 2x + 3y = 47(multiply \: by \: 3) \\  \\ 6x + 4y = 106\\ 6x + 9y = 141 \\  subtract \: both \: the \: equation \\  \\  - 5y =  - 35 \\( y = 7) \\  \\ put \: this \: in \: any \: of \: the \: equation \\ 2x + 3(7) = 47 \\ 2x + 21 = 47 \\ 2x = 26 \\ (x = 13)

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