Joan performed an experiment on two different types of cells and noted their sizes as follows:
Cells Size
Cell A 0.0005×10−5 m
Cell B 0.0025×10−7 m
What is the ratio of the size of cell A to the size of cell B?
Answers
Answered by
2
Answer:
Given:
The resistance of K2SO4 solution, R = 326 Ω
The cell constant = 4 m⁻¹
To Find:
The specific conductance of the given solution.
Calculation:
- We know the relation between the specific conductance, the cell constant and the resistance is:
Conductance = Cell constant / Resistance
⇒ κ = Cell constant / R
⇒ κ = 4 / 326
⇒ κ = 0.01227 S m⁻¹
⇒ κ = 1.227 × 10⁻⁴ S cm⁻¹
- So, the specific conductance of the given K2SO4 solution is 1.227 × 10⁻⁴ S cm⁻¹.
Answered by
0
Answer:
Step-by-step explanation:
step 1:
0.0005×10^-5 should be changed to 0.05×10^-7
step 2:
to make it easier to understand write both notations as fractions
0.05×10^-7/0.0025×10^-7
that is
20:1
answer is 20:1
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