Question

Joan performed an experiment on two different types of cells and noted their sizes as follows:

Cells Size
Cell A 0.0005×10−5 m
Cell B 0.0025×10−7 m
What is the ratio of the size of cell A to the size of cell B?

Answer 1

Answer:

Given:

The resistance of K2SO4 solution, R = 326 Ω

The cell constant = 4 m⁻¹

To Find:

The specific conductance of the given solution.

Calculation:

- We know the relation between the specific conductance, the cell constant and the resistance is:

Conductance = Cell constant / Resistance

⇒ κ = Cell constant / R

⇒ κ = 4 / 326

⇒ κ = 0.01227 S m⁻¹

⇒ κ = 1.227 × 10⁻⁴ S cm⁻¹

- So, the specific conductance of the given K2SO4 solution is 1.227 × 10⁻⁴ S cm⁻¹.

Answer 2

Answer:

Step-by-step explanation:

step 1:

0.0005×10^-5 should be changed to 0.05×10^-7

step 2:

to make it easier to understand write both notations as fractions

0.05×10^-7/0.0025×10^-7

that is

20:1

answer is 20:1