Question

Joel is working on his chemistry project and he has 300mL of 12% acid solution. (Include the graph where joel decrease the acidity)

If he needed to decrease the acidity of the solution w/c of the following is correct function that would show the new acidity of the solution given x mL of watet added?

a) f(x) = 36/300+x
b) f(x)= 0.36/300+x
c) f(x)= 12/300+x
d) f(x)= 0.12/300+x

And if joel decided to decrease the acidity of the solution by adding 15 more every interval w/c table of value is correct?

A.)
X
f(x) in %

1
11.43%

2
10.91%

3
10.43%

4
10%

B.)
X
f(x) in %

1
0.1143%

2
0.1091%

3
0.1043%

4
0.10%

C.)
X
f(x) in %

1
3.81%

2
3.64%

3
3.48%

4
3.33%

D.)

X
f(x) in %

1
3.81%

2
3.64%

3
3.48%

4
3.33%

I WILL MARK AS BRAINLIEST IF ANYBODY WILL ANSWER IT SERIOUSLY ✔​

Answer 1

Answer:

Yan po correct me if I'm wrong

Answer 2

The Correct option for the Function that shows new acidity after adding xml of water and decrease in acidity of the Solution is 'A' .

Given:-

Volume of Acidic Solution = 300ml

Strength of Solution = 12%

To Find:-

The Correct function that would show the new acidity of the solution when x mL of water is added. And also the decrease in acidity of the Solution.

Solution:-

To find the Correct function and decrease in acidity of the Solution, you should have to follow these simple steps which includes.

Volume of Acidic Solution (v) = 300ml

Strength of Solution (s) = 12%

Volume Strength = Volume of Acidic Solution * Strength of Solution

$vs = v \times s$

$vs = 300 \times \frac{12}{100}$

$vs = 3 \times 12$

$vs = 36$

Now, for writing the function that shows new acidity of the solution after adding x ml of water.

$f(x) = \frac{vs}{total \: volume}$

$f(x) = \frac{36}{(300 + x)}$

And, after solving the function f(x) in percentage or the decrease in acidity of the solution is 11.34%.

Hence, the Correct option for the Function that shows new acidity after adding xml of water and decrease in acidity of the Solution is 'A' .

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