John and Jivika together have 45 marbles. both of them lost 5 marbles each, and the product of the no of marbles they have is 128. Form the quadratic equation to find how many marbles they had to start with, if John had x marbles.
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Step-by-step explanation:
x+y=45
y=45-x
(x-5)×(y-5)=128
(x-5)×(45-x-5)=128
x^2-45x+200=0
x(x-40)-5(x-40)=0
(x-40)(x-5)=0
x=40 or 5
Answered by
0
Answer:
We find that John and Jivanti have got a total of 45 marbles.
Let us consider John is having x marbles
Jivanti is having (45-x) marbles.
Number of marbles John had after losing 5 marbles = x-5
After losing 5 marbles the number of marbles Jivanti had = (45-x)-5 = 40-x
Now coming back to the question, the product of the marbles that they are having now is 128
Now, (x-5)(40-x) = 128
= 40x –x2 – 200= 128
= x2 – 45x + 128 + 200 = 0
= x2 – 45x + 328 = 0
Therefore, the required quadratic equation is x2 – 45x + 328 = 0
Step-by-step explanation:
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