john covers a distance by driving a car at 60 kmphand he return back to the starting point on the scooter att 40kmph find the average speed for the whole journey
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if any particle or body moves with V1 speed for some distance , and again particle moves backward same distance with speed V2 , then
average speed = 2V1V2/(V1 + V2)
here
V1 =60 km/h
and V2 = 40 km/h
so, average speed = 2×60×40/(60+40)
=4800/100 = 48 km/h
average speed = 2V1V2/(V1 + V2)
here
V1 =60 km/h
and V2 = 40 km/h
so, average speed = 2×60×40/(60+40)
=4800/100 = 48 km/h
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solution ;-
let we assume that the distance covered be 'x'
and the total distance be '2x'
therefore, the time that covers distance by john with his car be x/ 60
Now, the time taken to return with his scooter is x/40
so, the total time = (x/60) + (x/40) = 5x/120
Now, avg speed = total distance / total time
=2x/(5x/120)
=48km/hr.
hence, the avg speed for the whole journey is 48km/hr.
let we assume that the distance covered be 'x'
and the total distance be '2x'
therefore, the time that covers distance by john with his car be x/ 60
Now, the time taken to return with his scooter is x/40
so, the total time = (x/60) + (x/40) = 5x/120
Now, avg speed = total distance / total time
=2x/(5x/120)
=48km/hr.
hence, the avg speed for the whole journey is 48km/hr.
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