Question

John got 50% of the questions correct on a 40-question test and 80% on a
80-question test. What percent of all questions did John get correct?

Answer 1

Answer:

70%

Step-by-step explanation:

50% of questions in 40 marks,

Therefore, number of correct questions

= $\frac{50}{100}$ × 40 = 20

80% of questions in 80 marks,

Therefore, number of correct questions

= $\frac{80}{100}$ × 80 = 64

Total number of questions = 40 + 80 = 120

Total number of correct questions = 20 + 64 = 84

Therefore,

Percentage of correct questions

⇒ $\frac{84}{120}$ × 100

⇒ 7 × 10

⇒ 70%

Answer 2

Answer: Percentage of all questions that John got correct = 70%

Step-by-step explanation: Question correct in 40-question test =50%

                                             Question correct in 80-question test = 80%

let 40- question test be Test 1 and 80-question test be test 2

Then , In test 1

Questions correct = 50/100 * 40

                               = 20 questions

In test 2

Questions correct = 80/100 * 80

                              = 64 questions

total questions correct = 20 + 64

                                        = 84 questions

Total Questions = 80 + 40 = 120

Percentage = $\frac{Correct questions}{Total Questions } * 100$

                    = $\frac{84}{120} * 100$

Percentage = 70%