john has bought a 4 gbyte mp3 player. (you may assume: 1 byte = 8 bits, 1 mbyte = 1024 kbytes and 1 mbyte = 1024 mbytes) (i) we can assume that each song lasts 3 minutes and is recorded at 128 kbps (kilobits per second). how much memory is required per song? (ii) using your answer in (i), how many songs can be stored on john's mp3 player?
Answers
Answer:
John's 4 GB MP3 player can store approximately 1,455 songs with each song lasting 3 minutes and recorded at 128 kbps.
Explanation:
(i) To calculate the memory required per song, we need to consider the duration and the bit rate of the audio.
First, we need to convert the song duration from minutes to seconds. Since there are 60 seconds in a minute, the song duration is 3 minutes * 60 seconds/minute = 180 seconds.
Next, we convert the bit rate from kilobits per second (kbps) to kilobytes per second (KB/s). Since 1 byte is equal to 8 bits, the bit rate is 128 kbps * (1 byte/8 bits) = 16 KB/s.
To calculate the memory required per song, we multiply the duration (in seconds) by the bit rate (in KB/s): 180 seconds * 16 KB/s = 2,880 kilobytes (KB).
(ii) To determine the number of songs that can be stored on John's 4 GB MP3 player, we need to convert the storage capacity to kilobytes (KB). Since 1 GB is equal to 1024 MB and 1 MB is equal to 1024 KB, the MP3 player has a total storage capacity of 4 GB * 1024 MB/GB * 1024 KB/MB = 4,194,304 KB.
Now, we divide the total storage capacity by the memory required per song: 4,194,304 KB / 2,880 KB = 1,455.1 songs (approximately).
To know more about the concept please go through the links:
https://brainly.in/question/4675647
https://brainly.in/question/55111937
#SPJ1