John is 4 times as old as Mary. The sum of their ages 6 years from now will be 3 more than 6 times John present age. The age of John is
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Let the questioner’s age be Q and that of his brother, B.
B = 4Q …(1)
B+5 = 2(Q+5) … (2), or
4Q+5 = 2Q+10, or
4Q-2Q = 10–5, or
2Q = 5, or
Q = 2.5, So B = 4*2.5 = 10.
In ten year’s time the questioner will be 12.5 years.
B = 4Q …(1)
B+5 = 2(Q+5) … (2), or
4Q+5 = 2Q+10, or
4Q-2Q = 10–5, or
2Q = 5, or
Q = 2.5, So B = 4*2.5 = 10.
In ten year’s time the questioner will be 12.5 years.
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