Question

John leaves for school at the same time every day. At 15 km/h he reaches school at 8 am. At 40 km/h he reaches school at 7 am. At what speed must he ride to reach school at 7:24 am (in km​

Answer 1

Answer:Hello Friend !

The answer to your query is given below. Please refer it !

As given in the question, the student walks from his house at 6:30 a.m. and reaches his school at 7:15 a.m. .

Therefore, the total time taken to reach the school is :

7:15 - 6 : 30 = 45 min. = 45 × 60 = 2700 sec [ ∵ 1 min = 60 sec ]

Also, total distance between the school and the home = 6 km = 6 × 1000 = 6000 m [ ∵ 1 km = 1000 m ]

Now, speed = distance / time

⇒ speed = \frac{6000}{2700}

2700

6000

​

⇒ speed = 2.22 m/s ≈ 2 m/s

Or 45 min = \frac{45}{60}

60

45

​

hr

⇒ speed = \frac{6 km * 60}{45 hr}

45hr

6km∗60

​

= 8 km/hr

Hope this helps !!!