Question

John travels 2m with speed v1 and again 2m with speed v2.what is his average speed?​

Answer 1

Answer:

Avg speed = (v1+v2)/2------(i)

Total distance =2m +2m=4m

Avg speed = total distance /total time taken

So,

4m/x =(v1+v2) /2

Answer 2

Answer:

Explanation:

Let's take d=2m

                  v=v1

and D=2m

        v=v2

Avg speed=Total distance / Total time

We have total distance as d+D= 4 m

But what about total time ?

So ,

Let s take those as t1 and t2 for speeds v1 and v2 respectively.

T=D/S;

Thus,

t1 = 2/v1 and t2 = 2/v2.

okay , so now , Finding avg speed :

Avg speed = d+D/t1+t2

[t1+t2 = 2/v1 + 2/v2 = 2(v1+v2)/v1+v2]

Avg speed = 4 / 2(v1+v2)/v1+v2

That implies =) 4 * v1+v2 upon v1 +v2.

It is requested tha pls Put this down on a paper and then understand it.

      You will surely understand!